A miniature poodle named "Sage" was crowned "Best in Show" on Tuesday at the 148th annual Westminster Kennel Club Dog Show, fetching the grand prize in the most prestigious competition among pure-bred canines in the United States.
The finalist representing all breeds classified as non-sporting dogs, Sage emerged victorious from more than 2,500 top-ranked canines competing in a two-day contest held at the USTA Billie Jean King National Tennis Center in the Queens borough of New York City.
Sage, a 4-year-old black-colored female groomed in the fine, fluffy topiary style traditional for poodles, competed head-to-head against the winners in six other groups: terriers, hounds, herding dogs, working dogs, sporting dogs and toy dogs.
She was the first female to win the top prize at Westminster since 2020, according to commentators on the Fox Sports channel, which broadcast the event live.
The Westminster Dog Show bills itself as the second-oldest U.S. sporting event, behind only the Kentucky Derby thoroughbred horse race. This year's competition drew a field of contenders representing 200 breeds from all 50 U.S. states and 12 other countries.
"Mercedes," a female 4-year-old German shepherd, was named runner-up for the overall contest after first winning the top prize in the herding dog group.
Along with Sage and Mercedes, the two other finalists chosen on Monday were "Comet," the Shih Tzu, representing the toy group, and "Louis," the Afghan hound leading the hound group.
Rounding out the finalists were three group winners chosen on Tuesday – "Micah," the black cocker spaniel, representing sporting dogs; "Monty," the giant schnauzer, leading the working dogs; and "Frankie," a colored bull terrier from the terrier group.
